500 no. of bricks (brick size – 20cm.*10cm.*10cm.) required for 1 cum of brick masonry.
and suppose, ratio = 1:6
then, sum = 1+6 = 7
We use 30% mortar in brick work, So 1 cum of brickwork has 0.3 cum of mortar. Quantity for 1:6 mortar mix
as we know, total dry mortar required for 1 cum. of brick masonry = 0.30 cum.
Therefore following dry material required.
Cement = 1* 0.30/7 = .04 cum. *(1/0.0347) = 1.15 bags.
Density of cement = 1440Kg/cum
So 1 bag of Cement Density=50/1440 = 0.0347Kg
Sand = 6* 0.30/7 = 0.26 cum.
or 0.26 cum. * 35.3 = 9.18 cft.
Material required for 1 cum. of brick masonry in mortar
ratio of 1:6.
Cement = 1.15 bags.
Sand = 9.18 cft.
Bricks = 500 nos.
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Why the mortar quantity (i.e 0.3cum/per cum of brick work) .If the brick size is 20cm*10cm*10cm then volume of one brick=0.002cum
If we deduct the mortar then only brick volume = 1.0-0.3=0.7cum
Total bricks required= 0.7/0.002=350nos.
Why the mortar volume is not deducted in brick masonry?
As we know 0.3cum (1:6)of mortar required in 1 cum of brick work
If the brick size is 20cm*10cm*10cm
The volume of one brick=0.002cum
Total bricks required in 1cum of brick masonry after deducting mortar=0.7/0.002=350nos
Please clarify.
Thanks a lot