500 no. of bricks (brick size – 20cm.*10cm.*10cm.) required for 1 cum of brick masonry.

and suppose, ratio = 1:6

then, sum = 1+6 = 7

We use 30% mortar in brick work, So 1 cum of brickwork has 0.3 cum of mortar. Quantity for 1:6 mortar mix

as we know, total dry mortar required for 1 cum. of brick masonry = 0.30 cum.

Therefore following dry material required.

Cement = 1* 0.30/7 = .04 cum. *(1/0.0347) = 1.15 bags.

Density of cement = 1440Kg/cum

So 1 bag of Cement Density=50/1440 = 0.0347Kg

Sand = 6* 0.30/7 = 0.26 cum.

or 0.26 cum. * 35.3 = 9.18 cft.

Material required for 1 cum. of brick masonry in mortar

ratio of 1:6.

Cement = 1.15 bags.

Sand = 9.18 cft.

Bricks = 500 nos.

It is so interesting that i like it much.

Very much good information and informative. Many thanks

very usefull

Why the mortar quantity (i.e 0.3cum/per cum of brick work) .If the brick size is 20cm*10cm*10cm then volume of one brick=0.002cum

If we deduct the mortar then only brick volume = 1.0-0.3=0.7cum

Total bricks required= 0.7/0.002=350nos.

Why the mortar volume is not deducted in brick masonry?

As we know 0.3cum (1:6)of mortar required in 1 cum of brick work

If the brick size is 20cm*10cm*10cm

The volume of one brick=0.002cum

Total bricks required in 1cum of brick masonry after deducting mortar=0.7/0.002=350nos

Please clarify.

Thanks a lot